Enumerative problem W(W)2(W)2W = 5 on Fl(3;7)

Experimental data
Number of Real Solutions
  Necklaces     1     3     5  
  dccbba     0     0     100000  
  dccbab     0     0     100000  
  dccabb     0     0     100000  
  dcbcba     0     0     100000  
  dcbcab     0     0     100000  
  dcbbca     0     0     100000  
  dcbbac     0     0     100000  
  dcbacb     0     0     100000  
  dcbabc     0     0     100000  
  dcacbb     0     0     100000  
  dcabcb     0     0     100000  
  dbccba     0     0     100000  
  dbccab     0     0     100000  
  dbcbca     0     0     100000  
  dbcacb     0     0     100000  
  dbbcca     0     0     100000  
Key
Condition Name Symbol Codimension
 124   W   a   1 
 125   W   b   2 
 134   W   c   2 
 126   W   d   3 
Point Selection
Total time of computation: 201 453.07 GHz-seconds or 2.33 GHz-days on rcf1422-2
1 600 000 Polynomial systems solved
The coefficients of a typical eliminant had 33 digits.
The typical eliminant had size 224 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 16:00:41 CDT 2005