Enumerative problem (A2315)4 = 2 on Fl(2,4;6)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  AAAA     0     1000  
Projections
VarietyProblem#
Fl(2;6) (W)4 1
Key
Condition Name Symbol Codimension
 2315   A2315   A   3 
Point Selection
Total time of computation: 468.87 GHz-seconds or 7.81 GHz-minutes on Schubert
1 000 Polynomial systems solved
The coefficients of a typical eliminant had 18 digits.
The typical eliminant had size 65 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:55:19 CDT 2005