Enumerative problem A2315(W)5(Y)2 = 10 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     0     2     4     6     8     10  
  Abbaaaaa     0     0     0     0     0     10000  
  Abaaaaab     0     0     0     0     0     10000  
  Abaaabaa     0     0     0     3165     4162     2673  
  Aaabbaaa     0     0     0     3273     4185     2542  
  Abaabaaa     0     0     0     3296     4020     2684  
  Ababaaaa     0     0     598     2804     3497     3101  
  Abaaaaba     0     0     670     2762     3530     3038  
  Aabbaaaa     0     0     853     2745     3287     3115  
  Aababaaa     0     173     3151     2973     2499     1204  
  Aabaaaba     0     221     2990     3081     2564     1144  
  Aaababaa     0     447     1373     3266     3874     1040  
  Aabaabaa     0     490     1471     3177     3890     972  
Key
Condition Name Symbol Codimension
 2315   A2315   A   3 
 1324   W   a   1 
 1245   Y   b   2 
Point Selection
Total time of computation: 293 539.98 GHz-seconds or 3.39 GHz-days on Witherlin
120 000 Polynomial systems solved
The coefficients of a typical eliminant had 91 digits.
The typical eliminant had size 1052 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:55:20 CDT 2005