Enumerative problem A2315(A1326)3 = 2 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  ABBB     0     2000  
Key
Condition Name Symbol Codimension
 2315   A2315   A   3 
 1326   A1326   B   3 
Point Selection
Total time of computation: 478.12 GHz-seconds or 7.97 GHz-minutes on Schubert
2 000 Polynomial systems solved
The coefficients of a typical eliminant had 45 digits.
The typical eliminant had size 144 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:55:13 CDT 2005