Enumerative problem (A1425)3(W)2Y = 8 on Fl(2,4;6)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
4
6
8
AAAaab
0
0
0
0
2000
AAAaba
0
0
0
0
2000
AAaAab
0
0
0
0
2000
AAaAba
0
0
0
0
2000
AAaaAb
0
0
0
0
2000
AaAaAb
0
0
0
0
2000
Projections
Variety
Problem
#
Fl(2;6)
(W)2(W)3
4
Key
Condition
Name
Symbol
Codimension
1425
A1425
A
3
1324
W
a
1
1235
Y
b
1
Point Selection
Total time of computation: 14 482.48 GHz-seconds or 4.02 GHz-hours on Noether
12 000 Polynomial systems solved
The coefficients of a typical eliminant had 127 digits.
The typical eliminant had size 1187 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:54:57 CDT 2005
)2Y
= 8 on Fl(2,4;6)
)2(W
)3
