Enumerative problem (A1425)3A1326 = 2 on Fl(2,4;6)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
AAAB
0
2000
Projections
Variety
Problem
#
Fl(4;6)
(Y)3Y
1
Key
Condition
Name
Symbol
Codimension
1425
A1425
A
3
1326
A1326
B
3
Point Selection
Total time of computation: 854.45 GHz-seconds or 14.24 GHz-minutes on Schubert
2 000 Polynomial systems solved
The coefficients of a typical eliminant had 11 digits.
The typical eliminant had size 42 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:54:54 CDT 2005
)3Y