Enumerative problem (A1425)2A2315A1326 = 2 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  ABAC     0     10000  
  AABC     1186     8814  
Key
Condition Name Symbol Codimension
 1425   A1425   A   3 
 2315   A2315   B   3 
 1326   A1326   C   3 
Point Selection
Total time of computation: 4 365.08 GHz-seconds or 1.21 GHz-hours on Schubert
20 000 Polynomial systems solved
The coefficients of a typical eliminant had 13 digits.
The typical eliminant had size 50 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:54:47 CDT 2005