Enumerative problem (A1425)2(A1326)2 = 2 on Fl(2,4;6)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
ABAB
0
2000
AABB
152
1848
Projections
Variety
Problem
#
Fl(4;6)
(Y)2(Y)2
1
Key
Condition
Name
Symbol
Codimension
1425
A1425
A
3
1326
A1326
B
3
Point Selection
Total time of computation: 727.69 GHz-seconds or 12.13 GHz-minutes on Schubert
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 11 digits.
The typical eliminant had size 42 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:54:46 CDT 2005
)2(Y
)2