Enumerative problem A1425(A2315)2A1326 = 2 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  ABBC     0     2000  
  ABCB     0     2000  
Key
Condition Name Symbol Codimension
 1425   A1425   A   3 
 2315   A2315   B   3 
 1326   A1326   C   3 
Point Selection
Total time of computation: 829.86 GHz-seconds or 13.83 GHz-minutes on Schubert
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 14 digits.
The typical eliminant had size 52 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:54:44 CDT 2005