Enumerative problem A1425A1534(W)2(Y)2 = 5 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     1     3     5  
  BaaAbb     0     0     5000  
  BaabAb     0     208     4792  
  BabAba     0     217     4783  
  BbaAab     0     217     4783  
  BaAabb     0     233     4767  
  BaAbba     0     421     4579  
  BbAaab     0     421     4579  
  BabAab     0     548     4452  
  BAaabb     0     729     4271  
  BAbbaa     0     729     4271  
  BaAbab     0     958     4042  
  BabaAb     0     984     4016  
  BAabab     0     2392     2608  
  BAbaba     0     2392     2608  
  BAabba     0     2851     2149  
  BAbaab     0     2851     2149  
Key
Condition Name Symbol Codimension
 1425   A1425   A   3 
 1534   A1534   B   5 
 1324   W   a   1 
 1235   Y   b   1 
Point Selection
Total time of computation: 4 426.36 GHz-seconds or 1.23 GHz-hours on rcf1422-5
80 000 Polynomial systems solved
The coefficients of a typical eliminant had 17 digits.
The typical eliminant had size 127 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:54:42 CDT 2005