Enumerative problem (A1325)3A2415Y = 12 on Fl(2,4;6)
Experimental data
Number of Real Solutions
Necklaces
0
2
4
6
8
10
12
BAaAA
0
0
0
0
67027
31380
1593
BaAAA
0
0
0
52260
45494
2246
0
Key
Condition
Name
Symbol
Codimension
1325
A1325
A
2
2415
A2415
B
4
1245
Y
a
2
Point Selection
Total time of computation: 491 576.52 GHz-seconds or 5.68 GHz-days on TAMU
200 000 Polynomial systems solved
The coefficients of a typical eliminant had 37 digits.
The typical eliminant had size 549 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:54:17 CDT 2005