Enumerative problem A1325(A2315)2(Y)2 = 6 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     0     2     4     6  
  BBaaA     0     557     3926     5517  
  BBaAa     0     978     4871     4151  
  BaBaA     0     1508     7250     1242  
  BaaBA     0     3878     3775     2347  
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2315   A2315   B   3 
 1245   Y   a   2 
Point Selection
Total time of computation: 9 910.17 GHz-seconds or 2.75 GHz-hours on Chevalley
40 000 Polynomial systems solved
The coefficients of a typical eliminant had 59 digits.
The typical eliminant had size 443 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:53:23 CDT 2005