Enumerative problem A1325A2315A1326WY = 3 on Fl(2,4;6)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  BCbAa     0     2000  
  BCbaA     0     2000  
  BbCAa     43     1957  
  BCAba     130     1870  
  BbaCA     333     1667  
  BCAab     577     1423  
  BACba     622     1378  
  BAbCa     736     1264  
  BbACa     866     1134  
  BCaAb     936     1064  
  BbCaA     1037     963  
  BCabA     1229     771  
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2315   A2315   B   3 
 1326   A1326   C   3 
 2314   W   a   2 
 1245   Y   b   2 
Point Selection
Total time of computation: 1 605.10 GHz-seconds or 26.75 GHz-minutes on Schubert
24 000 Polynomial systems solved
The coefficients of a typical eliminant had 40 digits.
The typical eliminant had size 175 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:53:22 CDT 2005