Enumerative problem A2315(X)3(Z)2 = 2 on Fl(2,4;5)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  Abbaaa     0     25000  
  Ababaa     0     25000  
  Abaaab     0     25000  
  Abaaba     1840     23160  
  Aabbaa     7275     17725  
  Aababa     11951     13049  
Key
Condition Name Symbol Codimension
 2315   A2315   A   3 
 1324   X   a   1 
 1235   Z   b   1 
Point Selection
Total time of computation: 5 396.58 GHz-seconds or 1.50 GHz-hours on Schur
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 21 digits.
The typical eliminant had size 72 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:38 CDT 2005