Enumerative problem A2315(X)3Z = 2 on Fl(2,4;5)



Experimental data
Number of Real Solutions
  Necklaces     0     2  
  Abaaa     0     25000  
  Aabaa     6181     18819  

Key
Condition Name Symbol Codimension
 2315   A2315   A   3 
 1324   X   a   1 
 1245   Z   b   2 
Point Selection

Total time of computation: 4 580.85 GHz-seconds or 1.27 GHz-hours on Schur
50 000 Polynomial systems solved
The coefficients of a typical eliminant had 15 digits.
The typical eliminant had size 56 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:37 CDT 2005