Enumerative problem A1435(X)3Z = 2 on Fl(2,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  Abaaa     0     25000  
  Aabaa     0     25000  
Projections
VarietyProblem#
Fl(4;5) ZZ 1
Key
Condition Name Symbol Codimension
 1435   A1435   A   4 
 1324   X   a   1 
 1235   Z   b   1 
Point Selection
Total time of computation: 4 045.30 GHz-seconds or 1.12 GHz-hours on Schur
50 000 Polynomial systems solved
The coefficients of a typical eliminant had 21 digits.
The typical eliminant had size 72 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:36 CDT 2005