Enumerative problem A1425(X)3(Z)2 = 2 on Fl(2,4;5)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
Abbaaa
0
25000
Ababaa
0
25000
Abaaba
0
25000
Abaaab
0
25000
Aabbaa
0
25000
Aababa
0
25000
Projections
Variety
Problem
#
Fl(4;5)
(Z)2Z
1
Key
Condition
Name
Symbol
Codimension
1425
A1425
A
3
1324
X
a
1
1235
Z
b
1
Point Selection
Total time of computation: 5 514.25 GHz-seconds or 1.53 GHz-hours on Schur
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 16 digits.
The typical eliminant had size 58 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:52:35 CDT 2005
)3(Z
)2 = 2 on Fl(2,4;5)
)2Z
