Enumerative problem A1325(X)3ZZ = 2 on Fl(2,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  Acbaaa     0     25000  
  Acabaa     0     25000  
  Acaaba     0     25000  
  Acaaab     0     25000  
  Abcaaa     0     25000  
  Abacaa     0     25000  
  Aacbaa     0     25000  
  Aabcaa     0     25000  
  Abaaca     1404     23596  
  Aacaba     1619     23381  
Projections
VarietyProblem#
Fl(4;5) (Z)2Z 1
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 1324   X   a   1 
 1235   Z   b   1 
 1245   Z   c   2 
Point Selection
Total time of computation: 7 381.75 GHz-seconds or 2.05 GHz-hours on Schur
250 000 Polynomial systems solved
The coefficients of a typical eliminant had 23 digits.
The typical eliminant had size 78 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:29 CDT 2005