Enumerative problem A1325(X)2(Z)2 = 2 on Fl(2,4;5)
Experimental data
Number of Real Solutions
Necklaces
0
2
Aaabb
0
25000
Aabba
0
25000
Aabab
6284
18716
Abaab
6410
18590
Key
Condition
Name
Symbol
Codimension
1325
A1325
A
2
1423
X
a
2
1235
Z
b
1
Point Selection
Total time of computation: 4 780.45 GHz-seconds or 1.33 GHz-hours on Schubert
100 000 Polynomial systems solved
The coefficients of a typical eliminant had 13 digits.
The typical eliminant had size 49 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:52:21 CDT 2005
)2(Z
)2 = 2 on Fl(2,4;5)
