Enumerative problem A1325A2315(X)2Z = 2 on Fl(2,4;5)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  BAbaa     0     24330  
  BAaab     0     24330  
  BbAaa     0     24330  
  BbaAa     0     24330  
  BaAba     10040     14290  
  BAaba     10743     13587  
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2315   A2315   B   3 
 1324   X   a   1 
 1235   Z   b   1 
Point Selection
Total time of computation: 4 723.35 GHz-seconds or 1.31 GHz-hours on Noether
145 980 Polynomial systems solved
The coefficients of a typical eliminant had 0 digits.
The typical eliminant had size 9 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:06 CDT 2005