Enumerative problem A1325A1435(X)2 = 2 on Fl(2,4;5)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
BAaa
0
25000
BaAa
0
25000
Projections
Variety
Problem
#
Fl(4;5)
ZZ
1
Key
Condition
Name
Symbol
Codimension
1325
A1325
A
2
1435
A1435
B
4
1324
X
a
1
Point Selection
Total time of computation: 3 957.25 GHz-seconds or 1.10 GHz-hours on Schur
50 000 Polynomial systems solved
The coefficients of a typical eliminant had 18 digits.
The typical eliminant had size 64 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:52:05 CDT 2005
)2 = 2 on Fl(2,4;5)
Z
