Enumerative problem A1325A1425(X)2Z = 2 on Fl(2,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  BAbaa     0     25000  
  BAaba     0     25000  
  BAaab     0     25000  
  BbAaa     0     25000  
  BbaAa     0     25000  
  BaAba     0     25000  
Projections
VarietyProblem#
Fl(4;5) (Z)2Z 1
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 1425   A1425   B   3 
 1324   X   a   1 
 1235   Z   b   1 
Point Selection
Total time of computation: 4 615.87 GHz-seconds or 1.28 GHz-hours on Schubert
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 15 digits.
The typical eliminant had size 54 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:52:04 CDT 2005