Enumerative problem A243(X)3Y = 2 on Fl(2,3;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  Aaaab     0     1000  
  Aaaba     0     1000  
  Aabaa     0     1000  
  Abaaa     0     1000  
Projections
VarietyProblem#
Fl(2;5) (X)3X 2
Key
Condition Name Symbol Codimension
 243   A243   A   4 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 123.37 GHz-seconds or 2.06 GHz-minutes on rcf1537-10
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 7 digits.
The typical eliminant had size 31 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:50:30 CDT 2005