Enumerative problem A243(X)2(Y)2 = 2 on Fl(2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  Aaabb     0     2000  
  Aabba     0     2000  
  Abbaa     0     2000  
  Aabab     460     1540  
  Abaab     466     1534  
  Ababa     520     1480  
Key
Condition Name Symbol Codimension
 243   A243   A   4 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 287.62 GHz-seconds or 4.79 GHz-minutes on rcf1422-3
12 000 Polynomial systems solved
The coefficients of a typical eliminant had 16 digits.
The typical eliminant had size 59 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:50:29 CDT 2005