Enumerative problem A143(X)2(Y)3 = 5 on Fl(2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3     5  
  Abbbaa     0     0     100000  
  Aaabbb     0     0     100000  
  Aabbba     0     19108     80892  
  Aabbab     0     41023     58977  
  Ababba     0     41288     58712  
  Abaabb     1582     30987     67431  
  Abbaab     1589     31071     67340  
  Aababb     13514     36862     49624  
  Abbaba     13637     36410     49953  
  Ababab     18049     43609     38342  
Key
Condition Name Symbol Codimension
 143   A143   A   3 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 370 663.46 GHz-seconds or 4.29 GHz-days on Ananke
1 000 000 Polynomial systems solved
The coefficients of a typical eliminant had 18 digits.
The typical eliminant had size 133 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:50:20 CDT 2005