Enumerative problem (A1432)2(A1254)2X = 2 on Fl(2,3,4;6)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
AABBa
0
2000
AABaB
0
2000
ABABa
0
2000
ABBAa
0
2000
Projections
Variety
Problem
#
Fl(3;6)
X(X)2(X)2
2
Fl(2,3;6)
(A143)2X(X)2
Fl(3,4;6)
(A1254)2X(X)2
Key
Condition
Name
Symbol
Codimension
1432
A1432
A
3
1254
A1254
B
3
1243
X
a
1
Point Selection
Total time of computation: 1 932.74 GHz-seconds or 32.21 GHz-minutes on Noether
8 000 Polynomial systems solved
The coefficients of a typical eliminant had 5 digits.
The typical eliminant had size 26 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:49:48 CDT 2005
= 2 on Fl(2,3,4;6)
(X
)2(X
)2