Enumerative problem A215(W)2(Y)3 = 2 on Fl(1,3;5)

Experimental data
Number of Real Solutions
  Necklaces     0     2  
  Abbbaa     0     25000  
  Abbaba     0     25000  
  Aabbba     0     25000  
  Ababba     1941     23059  
  Abbaab     7857     17143  
  Ababab     11951     13049  
Key
Condition Name Symbol Codimension
 215   A215   A   3 
 213   W   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 3 931.51 GHz-seconds or 1.09 GHz-hours on Ananke
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 20 digits.
The typical eliminant had size 71 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:48:45 CDT 2005