Enumerative problem A214A413(Y)2 = 2 on Fl(1,3;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  BAaa     0     25000  
  BaAa     0     25000  
Projections
VarietyProblem#
Fl(1;5) WW 1
Key
Condition Name Symbol Codimension
 214   A214   A   2 
 413   A413   B   4 
 124   Y   a   1 
Point Selection
Total time of computation: 3 987.88 GHz-seconds or 1.11 GHz-hours on Schur
50 000 Polynomial systems solved
The coefficients of a typical eliminant had 17 digits.
The typical eliminant had size 61 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:48:16 CDT 2005