Enumerative problem A214A314W(Y)2 = 2 on Fl(1,3;5)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
BAbba
0
25000
BAbab
0
25000
BAabb
0
25000
BbAba
0
25000
BbAab
0
25000
BbbAa
0
25000
Projections
Variety
Problem
#
Fl(1;5)
(W)2W
1
Key
Condition
Name
Symbol
Codimension
214
A214
A
2
314
A314
B
3
213
W
a
1
124
Y
b
1
Point Selection
Total time of computation: 5 548.14 GHz-seconds or 1.54 GHz-hours on Schur
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 28 digits.
The typical eliminant had size 93 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:48:15 CDT 2005
(Y
)2 = 2 on Fl(1,3;5)
)2W
