Enumerative problem A2135A2145(X)2X = 3 on Fl(1,2,4;5)
Experimental data
Number of Real Solutions
Necklaces
1
3
BbaAa
3256
21744
BbAaa
8546
16454
BAbaa
9849
15151
BbaaA
9903
15097
BAaba
11709
13291
BabAa
14939
10061
Key
Condition
Name
Symbol
Codimension
2135
A2135
A
2
2145
A2145
B
3
1324
X
a
1
1423
X
b
2
Point Selection
Total time of computation: 6 043.60 GHz-seconds or 1.68 GHz-hours on rcf1537-10
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 29 digits.
The typical eliminant had size 133 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:44:33 CDT 2005