Enumerative problem A1325(A2135)2(X)3 = 5 on Fl(1,2,4;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3     5  
  ABaaaB     0     170     24830  
  AaBBaa     773     10425     13802  
  ABBaaa     803     6411     17786  
  ABaBaa     4134     16429     4437  
  AaBaBa     7201     13595     4204  
  ABaaBa     8317     11766     4917  
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2135   A2135   B   2 
 1324   X   a   1 
Point Selection
Total time of computation: 9 300.60 GHz-seconds or 2.58 GHz-hours on Schubert
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 53 digits.
The typical eliminant had size 347 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:43:54 CDT 2005