Enumerative problem A1325A2135A3125(X)2 = 3 on Fl(1,2,4;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  CAaaB     0     25000  
  CABaa     975     24025  
  CBaAa     6994     18006  
  CaABa     9403     15597  
  CBAaa     9486     15514  
  CAaBa     12594     12406  
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2135   A2135   B   2 
 3125   A3125   C   3 
 1324   X   a   1 
Point Selection
Total time of computation: 5 786.81 GHz-seconds or 1.61 GHz-hours on Schubert
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 26 digits.
The typical eliminant had size 120 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:43:50 CDT 2005