Enumerative problem W(X)2(Y)2 = 2 on Fl(1,2,3;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  abbcc     0     1000  
  abcbc     0     1000  
  abccb     0     1000  
  acbbc     0     1000  
Projections
VarietyProblem#
Fl(2;5) (X)2(X)2 2
Fl(3;5) (Y)2(Y)2 2
Fl(1,2;5) W(X)2(X)2
Fl(2,3;5) (X)2(Y)2 2
Problems fibred over W(X)2(Y)2
VarietyProblem#
Fl(1,2,3,4;5) W(X)2(Y)2Z 2
Key
Condition Name Symbol Codimension
 213   W   a   1 
 142   X   b   2 
 134   Y   c   2 
Point Selection
Total time of computation: 335.63 GHz-seconds or 5.59 GHz-minutes on Schubert
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 25 digits.
The typical eliminant had size 84 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:43:28 CDT 2005