Enumerative problem A315W(X)2(Y)2 = 3 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  Accbba     0     25000  
  Abcacb     1852     23148  
  Acabbc     1990     23010  
  Acbcab     2198     22802  
  Aaccbb     2880     22120  
  Abccab     2946     22054  
  Acbacb     3128     21872  
  Acbbca     4899     20101  
  Accbab     5953     19047  
  Acacbb     7173     17827  
  Acabcb     7847     17153  
  Accabb     10786     14214  
  Acbcba     11048     13952  
  Aacbcb     11176     13824  
  Aabccb     11417     13583  
  Acbabc     11540     13460  
Key
Condition Name Symbol Codimension
 315   A315   A   4 
 213   W   a   1 
 132   X   b   1 
 124   Y   c   1 
Point Selection
Total time of computation: 9 251.38 GHz-seconds or 2.57 GHz-hours on Noether
400 000 Polynomial systems solved
The coefficients of a typical eliminant had 22 digits.
The typical eliminant had size 103 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:42:30 CDT 2005