Enumerative problem A215(W)2(X)3Y = 3 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  Acbbbaa     0     25000  
  Aacabbb     927     24073  
  Acabbba     2427     22573  
  Aacbbba     2509     22491  
  Acbbaba     4385     20615  
  Aabbcab     4501     20499  
  Acbbaab     5130     19870  
  Acaabbb     6026     18974  
  Aacbbab     6776     18224  
  Aabacbb     6958     18042  
  Abcbaab     8052     16948  
  Aaabbcb     8103     16897  
  Aabcbba     8401     16599  
  Aabcabb     8534     16466  
  Aaacbbb     8810     16190  
  Aaabcbb     9287     15713  
  Aabbacb     9355     15645  
  Abcabab     9589     15411  
  Aababcb     9697     15303  
  Acbaabb     11085     13915  
  Acbabba     11372     13628  
  Aabcbab     13018     11982  
  Abacbab     13125     11875  
  Acababb     13223     11777  
  Abaacbb     13264     11736  
  Abcaabb     13511     11489  
  Aacbabb     13525     11475  
  Acbabab     14647     10353  
  Abacabb     14735     10265  
  Acabbab     15028     9972  
Key
Condition Name Symbol Codimension
 215   A215   A   3 
 213   W   a   1 
 132   X   b   1 
 124   Y   c   1 
Point Selection
Total time of computation: 21 529.68 GHz-seconds or 5.98 GHz-hours on Schur
750 000 Polynomial systems solved
The coefficients of a typical eliminant had 41 digits.
The typical eliminant had size 180 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:42:21 CDT 2005