Enumerative problem A215W(X)2(Y)2 = 3 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  Aabbcc     0     25000  
  Abaccb     3372     21628  
  Accbab     3972     21028  
  Aacbbc     4498     20502  
  Aaccbb     6565     18435  
  Acabbc     6594     18406  
  Abcacb     7132     17868  
  Aabccb     8449     16551  
  Accabb     8880     16120  
  Aacbcb     9240     15760  
  Acabcb     9804     15196  
  Acbabc     10850     14150  
  Acbcab     11866     13134  
  Aabcbc     11870     13130  
  Acacbb     12699     12301  
  Acbacb     13342     11658  
Key
Condition Name Symbol Codimension
 215   A215   A   3 
 312   W   a   2 
 132   X   b   1 
 124   Y   c   1 
Point Selection
Total time of computation: 11 049.84 GHz-seconds or 3.07 GHz-hours on Pieri
400 000 Polynomial systems solved
The coefficients of a typical eliminant had 29 digits.
The typical eliminant had size 131 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:42:10 CDT 2005