Enumerative problem A214A315(X)3 = 3 on Fl(1,2,3;5)
Experimental data
Number of Real Solutions
Necklaces
1
3
BaAaa
9117
15883
BAaaa
11513
13487
Key
Condition
Name
Symbol
Codimension
214
A214
A
2
315
A315
B
4
132
X
a
1
Point Selection
Total time of computation: 5 005.02 GHz-seconds or 1.39 GHz-hours on Schur
50 000 Polynomial systems solved
The coefficients of a typical eliminant had 25 digits.
The typical eliminant had size 117 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:40:41 CDT 2005
)3 = 3 on Fl(1,2,3;5)
