Enumerative problem A214A315(X)2Y = 3 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3  
  BbaAa     0     25000  
  BaAba     1451     23549  
  BAbaa     3673     21327  
  BAaba     9515     15485  
  BAaab     12196     12804  
  BbAaa     14289     10711  
Key
Condition Name Symbol Codimension
 214   A214   A   2 
 315   A315   B   4 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 5 347.46 GHz-seconds or 1.49 GHz-hours on Schubert
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 22 digits.
The typical eliminant had size 104 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:40:40 CDT 2005