Enumerative problem A214A215(X)3Y = 5 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     1     3     5  
  BAbaaa     0     11592     13408  
  BbAaaa     0     14438     10562  
  BabAaa     1391     14970     8639  
  BaAbaa     1733     11736     11531  
  BaAaba     2323     9474     13203  
  BbaaAa     2711     13018     9271  
  BAaaba     3430     12961     8609  
  BbaAaa     4455     14091     6454  
  BAabaa     5195     13577     6228  
  BAaaab     8033     8708     8259  
Key
Condition Name Symbol Codimension
 214   A214   A   2 
 215   A215   B   3 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 16 304.07 GHz-seconds or 4.53 GHz-hours on Schubert
250 000 Polynomial systems solved
The coefficients of a typical eliminant had 73 digits.
The typical eliminant had size 466 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:40:32 CDT 2005