Enumerative problem A214A215(X)2(Y)2 = 4 on Fl(1,2,3;5)

Experimental data
Number of Real Solutions
  Necklaces     0     2     4  
  BabAba     0     1721     23279  
  BaAbba     0     2208     22792  
  BbbaAa     0     4332     20668  
  BbabAa     0     7567     17433  
  BAbaab     0     11897     13103  
  BbAaab     0     13283     11717  
  BbaAab     0     13810     11190  
  BAaabb     0     14918     10082  
  BAabab     0     16798     8202  
  BbaAba     179     6481     18340  
  BAabba     273     12305     12422  
  BAbbaa     306     8611     16083  
  BbbAaa     619     15726     8655  
  BbAbaa     632     10424     13944  
  BAbaba     1331     11911     11758  
  BbAaba     2947     11343     10710  
Key
Condition Name Symbol Codimension
 214   A214   A   2 
 215   A215   B   3 
 132   X   a   1 
 124   Y   b   1 
Point Selection
Total time of computation: 13 374.17 GHz-seconds or 3.72 GHz-hours on Noether
400 000 Polynomial systems solved
The coefficients of a typical eliminant had 56 digits.
The typical eliminant had size 303 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:40:31 CDT 2005