Enumerative problem A1325A2135A1524(X)3 = 5 on Fl(1,2,3,4;6)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     1     3     5  
  CaaaBA     0     0     15000  
  CaaaAB     0     0     15000  
  CaaBaA     0     1889     13111  
  CaaAaB     0     1889     13111  
  CBaaaA     0     3705     11295  
  CaaBAa     0     6536     8464  
  CaaABa     0     6536     8464  
  CaBaAa     0     8044     6956  
  CaBaaA     0     9848     5152  
  CaAaaB     0     9848     5152  
Projections
VarietyProblem#
Fl(3,4;6) A1254(X)3(Y)2
Fl(2,3,4;6) A1325A1524(X)3Y
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 2135   A2135   B   2 
 1524   A1524   C   4 
 1253   X   a   2 
Point Selection
Total time of computation: 119 240.14 GHz-seconds or 1.38 GHz-days on rcf1537-3
150 000 Polynomial systems solved
The coefficients of a typical eliminant had 78 digits.
The typical eliminant had size 492 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:39:13 CDT 2005