Enumerative problem (A1432)2(W)2(Z)2 = 2 on Fl(1,2,3,4;5)
Experimental data
Number of Real Solutions
Necklaces
0
2
AaAabb
0
1000
AaAbab
0
1000
AaaAbb
0
1000
AaabAb
0
1000
AabAba
0
1000
AabaAb
0
1000
AabAab
31
969
AAaabb
429
571
AAabab
506
494
AAabba
580
420
AAbaab
580
420
Key
Condition
Name
Symbol
Codimension
1432
A1432
A
3
2134
W
a
1
1235
Z
b
1
Point Selection
Total time of computation: 342.25 GHz-seconds or 5.70 GHz-minutes on Noether
11 000 Polynomial systems solved
The coefficients of a typical eliminant had 48 digits.
The typical eliminant had size 153 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:37:44 CDT 2005
)2(Z
)2 = 2 on Fl(1,2,3,4;5)
