Enumerative problem (A1432)2(W)2Z = 2 on Fl(1,2,3,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  AaAab     0     1000  
  AaaAb     0     1000  
  AAaab     416     584  
  AAaba     616     384  
Projections
VarietyProblem#
Fl(1,2,3;5) (A143)2(W)2Y 2
Key
Condition Name Symbol Codimension
 1432   A1432   A   3 
 2134   W   a   1 
 1245   Z   b   2 
Point Selection
Total time of computation: 256.83 GHz-seconds or 4.28 GHz-minutes on Noether
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 33 digits.
The typical eliminant had size 109 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:37:42 CDT 2005