Enumerative problem (A1432)2W(Z)2 = 2 on Fl(1,2,3,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  AaAbb     0     1000  
  AabAb     0     1000  
  AAabb     423     577  
  AAbab     616     384  
Projections
VarietyProblem#
Fl(2,3,4;5) (A1432)2X(Z)2 2
Key
Condition Name Symbol Codimension
 1432   A1432   A   3 
 3124   W   a   2 
 1235   Z   b   1 
Point Selection
Total time of computation: 235.68 GHz-seconds or 3.93 GHz-minutes on Noether
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 33 digits.
The typical eliminant had size 109 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:37:41 CDT 2005