Enumerative problem (A1432)2WZ = 2 on Fl(1,2,3,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  AaAb     0     1000  
  AAab     505     495  
Projections
VarietyProblem#
Fl(2,3;5) (A143)2XY 2
Fl(1,2,3;5) (A143)2WY 2
Fl(2,3,4;5) (A1432)2XZ 2
Key
Condition Name Symbol Codimension
 1432   A1432   A   3 
 3124   W   a   2 
 1245   Z   b   2 
Point Selection
Total time of computation: 216.05 GHz-seconds or 3.60 GHz-minutes on Noether
2 000 Polynomial systems solved
The coefficients of a typical eliminant had 18 digits.
The typical eliminant had size 65 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:37:40 CDT 2005