Enumerative problem (A1325)3WY = 5 on Fl(1,2,3,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     1     3     5  
  AAAba     0     0     2000  
  AAbAa     0     0     2000  
Projections
VarietyProblem#
Fl(2,4;5) (A1325)3(X)2 5
Fl(1,2,4;5) (A1325)3WX
Fl(2,3,4;5) (A1325)3XY
Key
Condition Name Symbol Codimension
 1325   A1325   A   2 
 3124   W   a   2 
 1342   Y   b   2 
Point Selection
Total time of computation: 620.47 GHz-seconds or 10.34 GHz-minutes on Schubert
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 16 digits.
The typical eliminant had size 120 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:37:39 CDT 2005