Enumerative problem (X)2(Y)2Z = 2 on Fl(2,3,4;5)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     0     2  
  aabbc     0     1000  
  aabcb     0     1000  
  ababc     0     1000  
  abbac     0     1000  
Projections
VarietyProblem#
Fl(2;5) (X)2(X)2 2
Fl(3;5) (Y)2(Y)2 2
Fl(2,3;5) (X)2(Y)2 2
Fl(3,4;5) (Y)2(Y)2Z
Problems fibred over (X)2(Y)2Z
VarietyProblem#
Fl(1,2,3,4;5) W(X)2(Y)2Z 2
Key
Condition Name Symbol Codimension
 1423   X   a   2 
 1342   Y   b   2 
 1235   Z   c   1 
Point Selection
Total time of computation: 256.23 GHz-seconds or 4.27 GHz-minutes on Schubert
4 000 Polynomial systems solved
The coefficients of a typical eliminant had 9 digits.
The typical eliminant had size 37 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:49:27 CDT 2005