Enumerative problem (A21436)2A21635(X)2 = 5 on Fl(1,3,5;6)
Experimental data
Number of Real Solutions
Necklaces
1
3
5
BAaAa
2741
6185
1074
BaAAa
2815
5979
1206
BAAaa
3104
6896
0
BAaaA
3244
5606
1150
Key
Condition
Name
Symbol
Codimension
21436
A21436
A
3
21635
A21635
B
5
12435
X
a
1
Point Selection
Total time of computation: 4 476.05 GHz-seconds or 1.24 GHz-hours on Schubert
40 000 Polynomial systems solved
The coefficients of a typical eliminant had 72 digits.
The typical eliminant had size 457 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:49:08 CDT 2005