Enumerative problem A21436A31526(X)5 = 16 on Fl(1,3,5;6)
Experimental data
Related Problems
Number of Real Solutions
Necklaces
0
2
4
6
8
10
12
14
16
BAaaaaa
0
0
0
0
0
0
0
0
7
BaAaaaa
0
0
0
0
0
0
0
0
7
BaaAaaa
0
0
0
0
0
0
0
0
7
Projections
Variety
Problem
#
Fl(3;6)
(X)6X
16
Fl(1,3;6)
A214A315(X)5
Fl(3,5;6)
A12436A13526(X)5
Key
Condition
Name
Symbol
Codimension
21436
A21436
A
3
31526
A31526
B
5
12435
X
a
1
Point Selection
Total time of computation: 767 316.86 GHz-seconds or 8.88 GHz-days on Calypso
21 Polynomial systems solved
The coefficients of a typical eliminant had 0 digits.
The typical eliminant had size 79 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:49:05 CDT 2005
)5 = 16 on Fl(1,3,5;6)
)6X