Enumerative problem (V)2(W)2WYYZZ = 5 on Fl(1,2,4,5;6)
Experimental data
Number of Real Solutions
Necklaces
1
3
5
cbbedfgaa
0
0
15000
cbbaaedfg
0
0
15000
cbbfgedaa
0
0
15000
cbbaafged
0
0
15000
cbbfgaaed
49
9624
5327
cbbedaafg
123
1729
13148
Key
Condition
Name
Symbol
Codimension
21345
V
a
1
13245
W
b
1
15234
W
c
3
12354
Y
d
1
13452
Y
e
3
12346
Z
f
1
12356
Z
g
2
Point Selection
Total time of computation: 99 332.95 GHz-seconds or 1.14 GHz-days on Noether
90 000 Polynomial systems solved
The coefficients of a typical eliminant had 111 digits.
The typical eliminant had size 692 bytes.
This table automatically generated from the data in This File using This Maple ScriptCreated: Fri Jul 15 15:46:16 CDT 2005
)2(W
)2W
Y
Y
Z
Z
= 5 on Fl(1,2,4,5;6)
